A body falls from a height of 120 m. After 2 s of fall, if gravity disappears then total time taken to reach the ground is (g = 10 m/s Square)
(a) 9 s (b) 5 s (c) 7 s (d) 10 s
Answers
Answered by
121
h = 120 meters
v = u + g t
= 0 + 10 m/s/s * 2 sec = 20 m/s
distance traveled in 2 sec
s = u t + 1/2 g t^2 = 0 + 1/2 * 10 * 2^2 = 20 meters
Distance to travel = 120 - 20 = 100 m
velocity = 20 m/sec is constant as there is no gravity.
time taken = 100 m/ 20 m/s = 5 seconds
v = u + g t
= 0 + 10 m/s/s * 2 sec = 20 m/s
distance traveled in 2 sec
s = u t + 1/2 g t^2 = 0 + 1/2 * 10 * 2^2 = 20 meters
Distance to travel = 120 - 20 = 100 m
velocity = 20 m/sec is constant as there is no gravity.
time taken = 100 m/ 20 m/s = 5 seconds
kvnmurty:
please click on thank you link and select best answer
Answered by
15
here is your answer OK ☺☺☺☺☺☺
u = 0 m/s
t = 2 seconds
g = 10 m/s2
h = ut + 1/2 g t2
h = 0 + 1/2 (10) 4 = 20 m
Remaining Distance = 199-20 = 179 m
v = u + gt = 0 + 10 x 2 = 20 m/s
Now, we have v = 20 m/s, no gravity and distance = 179 m
So, time = distance/speed = 179/20 = 89.5 seconds
So, total time = 89.5+2 = 91.5 seconds
u = 0 m/s
t = 2 seconds
g = 10 m/s2
h = ut + 1/2 g t2
h = 0 + 1/2 (10) 4 = 20 m
Remaining Distance = 199-20 = 179 m
v = u + gt = 0 + 10 x 2 = 20 m/s
Now, we have v = 20 m/s, no gravity and distance = 179 m
So, time = distance/speed = 179/20 = 89.5 seconds
So, total time = 89.5+2 = 91.5 seconds
Similar questions