Question

a body falls from a height of 200m .what is the distance travelled in each 2s ,during t=0 to t=6 of the journey

Answer 1

heya....


Distance in first two seconds is (1/2)g(2)² = 20

 in first four seconds is (1/2)g(4)² = 80 and

in first six seconds is (1/2)g(6)² = 180

so ratio of distance traveled in each two seconds is 20:(80-20):(180-80) = 20:60:100 = 1:3:5.


tysm.#gozmit

Answer 2

Answer:

1:3:5

1. Explanation:

t=0 tot=6s

s= ut+1/2at square

u=0

for t=2

1/2g(4)

for t=4

1/2g(16)

for t=6

1/2g(36)

S at t=2-t=0

=1/2g4 (4-0)

S at t=4 -t=2

=1/2g12 (16-4)

S at t=6-t=4

=1/2g(20) (36-16)

4:12:20

on dividing throughout by 4

=1:3:5