a body falls from a height of 500 in how much time will it strike the ground
Answers
Answer:
You can use the concept of conservation of total mechanical energy (neglecting the air resistance).
So, initially total mechanical energy = gravitational potential energy (kinetic energy is zero because initially there is no velocity).
Final total mechanical energy = kinetic energy (gravitational potential energy is zero because height has become zero).
So, initial mechanical energy = Final mechanical energy
(1/2)mv²=mgh
v(at height = 0) = √(2gh)
We can use this expression to find the maximum velocity or velocity just before touching the ground.
For this problem, v = √2×10×500 = 100m/s.
-: Fun fact : As we can see that from the equation that the final velocity of all falling objects is independent of the mass of the object. So, the time taken by every object if fallen from height ‘h' is always constant i.e equal to √(2h/g). You can verify this by letting a basket ball (heavier) and tennis ball (lighter) fall from same height. Both balls are going to fall at the same time. ;) This is only valid when air resistance is negligible for both objects. If you will try it with a paper and basket ball, then they are definitely not gonna fall at same time because paper is gonna experience large air resistance which will decrease its speed and hence the time, it will take to fall, will increase. :-
Explanation:
You can use the concept of conservation of total mechanical energy (neglecting the air resistance).
So, initially total mechanical energy = gravitational potential energy (kinetic energy is zero because initially there is no velocity).
Final total mechanical energy = kinetic energy (gravitational potential energy is zero because height has become zero).
So, initial mechanical energy = Final mechanical energy
(1/2)mv²=mgh
v(at height = 0) = √(2gh)
We can use this expression to find the maximum velocity or velocity just before touching the ground.
For this problem, v = √2×10×500 = 100m/s.
-: Fun fact : As we can see that from the equation that the final velocity of all falling objects is independent of the mass of the object. So, the time taken by every object if fallen from height ‘h' is always constant i.e equal to √(2h/g). You can verify this by letting a basket ball (heavier) and tennis ball (lighter) fall from same height. Both balls are going to fall at the same time. ;) This is only valid when air resistance is negligible for both objects. If you will try it with a paper and basket ball, then they are definitely not gonna fall at same time because paper is gonna experience large air resistance which will decrease its speed and hence the time, it will take to fall, will increase. :-
Answer:
Let acceleration = 10m/s^2
Distance is 500m
Initial velocity 0m/s
S= ut+1/2at^2
500= 0+1/2 ×10 (t)^2
(t)^2 = 500/5
= 100m
t= 10 sec
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Explanation: