A body falls from height 100m. At what height is P.E 1/3rd of K.E?
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Answered by
2
u = 0
V at a height h = {2g(100-h)}^1/2
Energy conservation
mgh = 1/2 mv^2
from here get 'h'
V at a height h = {2g(100-h)}^1/2
Energy conservation
mgh = 1/2 mv^2
from here get 'h'
Answered by
2
Hence, your desired distance = 75m
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Yuichiro13:
well I wonder if theres a shorter way =_=
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