A body falls from height of 500 m. In how much time will it strike the ground ?
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Answered by
6
Answer:
u=0(because object at start is at rest)
h=500m
t=?
h=ut+1/2gt2
500=0×t+1/2×10×t2
500=5×t2
100=t2
10s=t or
t=10s
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Answered by
0
Answer:
Let acceleration = 10m/s^2
Distance is 500m
Initial velocity 0m/s
S= ut+1/2at^2
500= 0+1/2 ×10 (t)^2
(t)^2 = 500/5
= 100m
t= 10 sec
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