Question

A body falls from rest. In the last two seconds it covers half of
the total distance. Find the total time of the journey and total
distance.​

Answer 1

Answer:

T=1.2s & 6.8s

S=7.2m & 231.2m

Explanation:

$let \: the \: distance \: cover \: i n \: t \: second \: be \\ initial \: velocity(u) = 0 \\ \\ s = \frac{1}{2} gt {}^{2} \\ \\ half \: of \: the \: total \: distance \: cover \: in(t - 2)second \\ be \\ \frac{1}{2} s = \frac{1}{2} g {(t - 2)}^{2} \\ \\ by \: dividing \: 1 \: from \: \ 2 \\t {}^{2} - 8t + 8 = 0(this \: is \: quadric \: eq) \\ \binom{ - b + - \sqrt{ {b}^{2} - 4ac } }{2a} \\ \\ by \: putting \: value \: you \: will \: get \: t = (4 - 2.8) = 1.2 \\ and \\ (4 + 2.8) = 6.8 \\ putting \: t = 1.2 \: in \: eq \: 1 \\ s = \frac{1}{2} g {t}^{2} \\ s = 7.2m$

Hope this helps

Mqrk as Brainliest.

thank You.