a body falls from rest . it covers as much distance in the last second of its motion as covered in the first three seconds. the body has fallen for a time
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S=ut+(1/2)*at*t
for first three seconds,s=(1/2)*g*9=9g/2.(u=0)
find distance covered in last second.
equate two distances.
im sure u will get the answer.
for first three seconds,s=(1/2)*g*9=9g/2.(u=0)
find distance covered in last second.
equate two distances.
im sure u will get the answer.
sayalilokhande:
can u explain me ?
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