Question

A body falls from rest the velocity acquired by falling a distance 2h is

Answer 1

Hola!!!⤵️⤵️

⭕

${v}^{2} - {u}^{2} = 2as$

${v}^{2} - 0 = 4ah$

$v = 2 \sqrt{as}$

Answer 2

Suppose the body falls through a further distance S

intial velocity=0 (u)

by equation of motion v'2-u'2=2gh

so v =(2gh)'1/2

v= sqrt(2gh)sqrt(2gh)......two times square

now since the body falls a distance by S

u = sqrt(2gh) sqrt (2gh)

v=?

v=sum

v=0+2*g*2h

2h is height...

v'2=4gh

v= 2(gh)'1/2

hopes helps you dearr mate