a body falls from rest under gravity. the distance moved by it during 2nd sec is
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A body is falling freely under gravity. What distance does it fall during an interval of time between the 1st and 2nd seconds of its motion if g=10?
A body is falling freely under gravity. What distance does it fall during an interval of time between the 1st and 2nd seconds of its motion if g=10?
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S = ut + 1/2gt^2
Here, u = 0 and g = 10
Total distance covered in two seconds -
S2 =| 0 * 2 + 1/2 (-10) 2^2 | = 20 m .
Total distance covered in one second -
S1 = | 0*1 + 1/2 ( -10) 1^2 | = 5 m .
=> Distance covered by body during an interval of time between first and second seconds of its motion = (S2 - S1 ) = 20–5 = 15m .
Explanation:
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