Question

a body falls from the top of a building and reaches the ground 2.5 seconds later. how high is the building?

[show me the process please.
The answer is given : 30.6m]​

Answer 1

I hope it would help

Answer 2

Answer:30.625m

Explanation:

Initial velo.(u)=0

Final velo=v

Time taken(t)=2.5 seconds

Height of building=?

Height of building= distance covered by it=S

Now we know,

S=ut+(1/2)gt^2

=0×2.5+(1/2)×9.8×(2.5)^2

=0+(61.25/2)

=30.625 m