A body falls from the top of a building and reaches the ground 2.5 seconds later. How high is the building?(Take g = 9.8 m/s^2)
Answers
Answered by
11
v =0
u=?
g=9.8m/s2
t=2.5 sec
v=u+gt
0=u+9.8×2.5
0=u+24.50
0-24.50=u
-24.50=u
v2-u2=2gh
(0)2-(-24.50)2 =2 ×9.8×h
0-590.2500=94.56×h
-590.25=94.56×h
-590.25÷94.56=h
u=?
g=9.8m/s2
t=2.5 sec
v=u+gt
0=u+9.8×2.5
0=u+24.50
0-24.50=u
-24.50=u
v2-u2=2gh
(0)2-(-24.50)2 =2 ×9.8×h
0-590.2500=94.56×h
-590.25=94.56×h
-590.25÷94.56=h
Similar questions