Question

A body falls from the top of a building and reaches the ground 2.5 s later. HOW high is the building? [ take g =9.8m/s2]

Answer 1

$h = ut + \frac{1}{2} a {t}^{2} \\ \: \: \: \: = 0 \times 2.5 + \frac{1}{2} \times 9.8 \times 2.5 \times 2.5 \\ \: \: \: \: = \frac{61.25}{2} \\ \: \: \: \: \: = 30.625m$
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Answer 2

h = ut + ½at² h = ut + ½gt² Here u = 0m/sec t = 2.5 sec g = 9.8m/s² h = 0(2.5) + ½(9.8)(2.5)² = 0+ ½(61.25) = 30.625m