A body falls from the top of a building and reaches the ground 2.5s latter. How high is the building? (g=9.8m/s²)
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Answer:
30.625 m
Explanation:
Initial velocity, u = 0 m/s
Acceleration due to gravity, g=9.8 m/s2
Time taken to reach the ground, t = 2.5 sec
Height, h = ?
Using relation,
s=u t+21gt2
s=0×2.5+21×9.8×2.5×2.5
s=0+4.9×2.5×2.5
s = 30.625 m
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