Physics, asked by IzzurBaby, 1 month ago

A body falls from the top of a building and reaches the ground 2.5s latter. How high is the building? (g=9.8m/s²)​

Answers

Answered by jeetchourasia7
1

Answer:

30.625 m

Explanation:

Initial velocity, u = 0 m/s

Acceleration due to gravity, g=9.8 m/s2

Time taken to reach the ground, t = 2.5 sec

Height, h = ?

Using relation,

s=u t+21gt2

s=0×2.5+21×9.8×2.5×2.5

s=0+4.9×2.5×2.5

s = 30.625 m

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Answered by morankhiraj
1

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