Question

A body falls from the top of a building reaches the ground in 3sec. Height of

the building is​

Answer 1

Answer:

45m

use the formula. s=ut+1/2at^2

Answer 2

Answer:

45m

Explanation:

According to the given question,

u = initial speed = 0 m/s ( As this is free fall)

t = 3s (To reach the ground)

a = g (gravity = 10 m/s^2)

And we are asked to find hight of the building.

We know , S = ut + 1/2 at^2

here u = 0 (from the given question)

so, S = 1/2 gt^2

putting the values,

S = 1/2 ×10 × 9

S = 45 m

Hence, the object travels 45 m which is hight of the building in 2.5 sec.