Question

A body falls from the top of the building and reaches the ground 2.5s later. How high is the building? (Take g=10m/s)

Answer 1

Answer:

31.25 m

Step-by-step explanation:

According to the given question,

u = initial speed = 0 m/s ( As this is free fall)

t = 2.5 s (To reach the ground)

a = g (gravity = 10 m/s^2)

And we are asked to find hight of the building.

We know , S = ut + 1/2 at^2

here u = 0 (from the given question)

so, S = 1/2 gt^2

putting the values,

• S = 1/2 ×10 × 6.25

• S = 31.25 m

Hence, the object travels 31.25 m which is hight of the building in 2.5 sec.

Answer 2

Answer:

31.25 m in a better way

Step-by-step explanation:

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