Question

a body Falls from the top of the tower and strikes the ground with a velocity of 18 metre per second .find the height of the tower?​

Answer 1

We have,

a = 9.8 m/s^2

v = 18 m/s

u = 0 m/s

Then;

2ah = v^2 - u^2

19.6h = 324

h = 16.53 m (approx.)

Hence, the height of the tower is 16.53m.

HOPE THIS COULD HELP !!!

Answer 2

Answer:16.2 meters

Explanation:

u = 0m/s

v = 18m/s

a = 10m/s (acceleration due to gravity )

s = ? (height)

USING THE FORMULA v^2 - u^2 = 2as

18^2 - 0^2 = 2*10*s

324-0 = 20s

s = 324/20

s = 16.2m