Physics, asked by aardrarameshnair, 1 year ago

A body fell from rest from a height H above the ground. In the last 1 sec of its fall,it traveled a distance H/2.Find the value of H.

Answers

Answered by ParaBoy
4

Answer:

10m

Explanation:

since it is fall from rest hence initial velocity is 0 and then then from formula of free falling we can calculate...

I hope it helps.....

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Answered by shyamshankar97
9

Answer:10

Explanation:.

We know that

S = ut + 1/2(gt^2)

Here the body is at free fall so initial velocity u= 0

The body travels H/2 distance in 1sec

So S = H/2

t = 1

g = 10

So by solving the equation

H/2 = 0+(10/2)*1

H = 10

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