A body fell from rest from a height H above the ground. In the last 1 sec of its fall,it traveled a distance H/2.Find the value of H.
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Answered by
4
Answer:
10m
Explanation:
since it is fall from rest hence initial velocity is 0 and then then from formula of free falling we can calculate...
I hope it helps.....
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Answered by
9
Answer:10
Explanation:.
We know that
S = ut + 1/2(gt^2)
Here the body is at free fall so initial velocity u= 0
The body travels H/2 distance in 1sec
So S = H/2
t = 1
g = 10
So by solving the equation
H/2 = 0+(10/2)*1
H = 10
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