Question

A body floats in water with 40℅ of its volume outside water.When the same body floats in oil ,60℅of its volume remains outside oil . The relative density of the oil is=?

Answer 1

hey!!

here is your answer...

A body floats in water with 40% of its volume outside of the water. When this body is kept in oil, it floats with 60% of its volume remaining outside of the oil. When the relative density of oil is K/2, what is the value of K?


Since the body is 60% submerged in water, it's density has to be 0.6 g/cc

Since the body remains 40% submerged in oil, the density of oil has to be 0.6/0.4=1.5 

Relative density = 1.5/1.0 = 1.5 = 3/2

hope it helps!

Answer 2

Answer:

Explanation:using the law of buoyancy, we have Vgd=0.6Vd1g, for the part of body outside oil and Vdg=0.4d2g,for the part of body outside water, hence we get

1=0.6d1/0.4d2

So we have, d1/d2=6/4=3/2=1.5