Question

A body floats with 1/3 of its volume outside water and 3/4 of its volume outside another liquid.The density of the other liquid is: (i)9/4 x 103kg/M3 (ii)4/9 x 103kg/M3 (ii)8/3 x 103kg/M3 (iv)3/9 x 103kg/M

Answer 1

volume = V
density= d
density of water =q = 1000 kg/m3
weight in air = w= Vgd
Buoyant force= (2V/3)qg

density of other liquid =p
volume of body inside water= V- 3V/4= V/4
buoyant force = (V/4)pg

as in both situation the body will float so, 
(2V/3)qg = (V/4)pg
p = 8q/ 3
p = 8 x 1000/3
p= 8 /3 x 10³

Answer 2

See the attachment. Hope it helps