A body floats with 40% of its volume outside water and 60% of its volume
outside another liquid x. The density of the liquid 'X is
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Step-by-step explanation:
Using the law of buoyancy, we have Vσg=0.6Vσ1g, for the part of body outside oil and Vσ2g, for the part of body outside water, hence we get
1=0.6σ10.4σ2
So, we have, σ1σ2=64=32=15 answer
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