A body freely falling body from a height h describes 7h/16 in the last second of its fall the height h is (PLEASE ANSWER FASTLY)
Answers
Answered by
8
☺❤
your answer is here =>
h=1/2gt^2---(.................i)
7h/16=g(t-0.5)--............(ii)
sub. (i) in (ii)
7[1/2(gt^2)]/16=g(t-0.5)
by simplifying we will get .
32t-16=7t^2
7t^2-32t+16=0
solving the equations we would get t=4
h=1/2(gt^2)=1/2(10*16)
=80m_____answer
your answer is here =>
h=1/2gt^2---(.................i)
7h/16=g(t-0.5)--............(ii)
sub. (i) in (ii)
7[1/2(gt^2)]/16=g(t-0.5)
by simplifying we will get .
32t-16=7t^2
7t^2-32t+16=0
solving the equations we would get t=4
h=1/2(gt^2)=1/2(10*16)
=80m_____answer
Similar questions