Physics, asked by areanshra12, 9 months ago

A body freely falling body from a height h describes 7h/16 in the last second of its fall the height h is (PLEASE ANSWER FASTLY) ​

Answers

Answered by nosumittiwari3
8
 \huge{hey--dear} ☺❤

your answer is here =>

h=1/2gt^2---(.................i)  

7h/16=g(t-0.5)--............(ii)  


sub. (i) in (ii)  

7[1/2(gt^2)]/16=g(t-0.5)  

by simplifying we will get .

32t-16=7t^2  

7t^2-32t+16=0  


solving the equations we would get t=4  


h=1/2(gt^2)=1/2(10*16)  
=80m_____answer

 <marquee > Hope it's help you
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