A body freely falling from a tower of height h covers a distance of 7/16h , during the last second of motion . Then the height of tower is ??
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The body falls through
h−(7h16)=9h16h−(7h16)=9h16 during (n−1)(n−1) seconds and fall through 'h' in n seconds
using s=ut+12s=ut+12at2at2
9h169h16=5(n−1)2=5(n−1)2
and h=5n2h=5n2
dividing 916=(n−1)2n2916=(n−1)2n2
we get n=4n=4
Therefore h=5×42=80m
h−(7h16)=9h16h−(7h16)=9h16 during (n−1)(n−1) seconds and fall through 'h' in n seconds
using s=ut+12s=ut+12at2at2
9h169h16=5(n−1)2=5(n−1)2
and h=5n2h=5n2
dividing 916=(n−1)2n2916=(n−1)2n2
we get n=4n=4
Therefore h=5×42=80m
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