Physics, asked by prajjwalrai, 1 year ago

a body freely falling from rest and has a velocity V after it has fall through height h. the distance it has to fall further for its velocity to become double is....

Answers

Answered by AJIT1258

Use
intial velocity u=0
at velocity=v height=h
therefore

then let intial velocity u=v
and final velocity=2v
therefore

the distance it has to fall down further for its velocity to become 2v is 3.times h

prajjwalrai: let me try

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prajjwalrai: please explain

prajjwalrai: ajit please explain

AJIT1258: The fallen velocity at any time has the relationship through the height of travel as V²=2gH.As per the question doubling its velocity makes as 2V so new distance traveled through being H' makes (2V)²=2gH’=>4V²=2gH’

=>H'=2V²/g=2×2gH/g=4H=>further falling distance to be 4H-H=3H.Ans..

Answered by Republican

for case 1
u is 0
a is g
applying kinematics eqn
so is v^2/2g
case 2
u is v
v is 2v
a is g
4v^2-v^2=2gs
s=3v^2/2g

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