A body freely falling from rest has acquired a velocity 'v' after it falls through a distance h. The distance it has to fall further for its velocity to become double is
The answer should be 3h according to my book's key.
I'm not getting the answer.
Please write the whole procedure step by step. I'll be needing the whole sum.
I will thank you and Mark as brainliest if you send the proper answer.
If the answer is irrelevant or improper I will report.
Thank you
Answers
Answered by
0
Answer:
v
2
=u
2
+2gh ....(1)
v
1
2
=u
2
+2g(h+x)... (2)
v
1
=2v
⇒4v
2
=2g(h+x)
8gh=2g(h+x)
x=3h
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