Question

A body freely under the action of gravity reaches the ground in 2 sec. find the height from which the body fell.(hint:her take g=9.81m/sec² in the place of acceleration).​

Answer 1

       $\underline{\bold{Answer:}}$

       $19.62 \text{ meters}$

       $\underline{\bold{Step-by-step-explaination:}}$

       $\text{It is given that a body freely under the action of gravity reaches the} \\\text{ground in 2 seconds}$

$\implies \text{Time taken}(t) = 2s$

       $\text{Acceleration due to gravity}(g) = 9.81ms^{-2}$

       $\text{Height from which the body fell}(h) = \text{ ?}$

       $\text{We know that, for a free falling body, }h = \frac{1}{2} gt^{2}$

$\implies h = \frac{1}{2}(9.81)(2)^{2}$

$\implies h = 2(9.81)$

$\implies h = 19.62 \text{ meters}$

Answer 2

Answer:

U = 0 ; T = 2 ; a = g = 9•8

Using

V = U + at

V = 0 + 9•8 × 2

V = 19•6m/s

Now,

S =

$s = ut + \frac{1}{2} a {t}^{2} \\s = 0 + \frac{1}{2}9.8 \times 2 \times 2 \\ s = 19.6m$

HOPE IT MAY HELP U