a body get displayed by 5m in 2min when a 20n force is applied on the body at 60°angle .find the work done and power (cos 60°=1/2)
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Answer:
F=10N,S=2m,θ=60
0
So, Work=F×Scosθ=10×2cos60
0
=10×2×
2
1
=10J
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