Question

a body goes 3M East, 4m north,4m east 3M North calculate magnitude of displacement

Answer 1

Howdy!!

your answer is ----


total displacement is

$\sqrt{ {4}^{2} + {3}^{2} } + \sqrt{ {4}^{2} + {3}^{2} } \\ = \sqrt{25} + \sqrt{25} \\ = 5 + 5 = 10meter$


hope it help you

Answer 2

hey mate
the magnitude of displacement is 10m.because in first two combination of 3 east and 4 north,the hepotaneous is 5m which is displacement and again in next 4 east and 3 north again 5m is displacement.so, the total displacement=10m