Question

A body has a mass of 50 kg. Its velocity is brought
down from 20 m/s to 5 m/s by a resisting force in 5
. The magnitude of resisting force is​

Answer 1

Answer:

Explanation:

F = 150 N

Optiona →a

Given :-

M = 50 kg

u = 20 m/s

v = 5 m/s

t = 5s

First we have to find deaceleration produced by the resistive force in

Here , negative sign show the deaceleration produced by resistive force.

Now,

From Newton 2 nd law of motion,

The magnitude of force is given by :

here, Negative sign is due to the opposite direction of resistive force.

hence,the magnitude of resistive force is 150 N.

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Answer 2

Answer:

Explanation:150N