Question

A body has a velocity 300 cm/s. If it has a uniform acceleration of 10 cm/s2, find the distance it travels in 3 seconds.

Answer 1

Given:-

• Initial Velocity,u = 300 cm/s

• Acceleration,a = 10 cm/s²

• Time taken,t = 3 s

To be calculated:-

Calculate the distance (s) travelled by a body .

Formula used:-

s = ut + 1/2 at²

Solution:-

From the second equation of motion,

s = ut + 1/2 at²

★ Putting the values in the above formula,we get

s = 300 × 3 + 1/2 × 10 × ( 3 )²

s = 900 + 5 × 9

s = 900 + 45

s = 945 cm

Thus, the distance travelled by a body is 945 centimetres.

Answer 2

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A body has a velocity 300 cm/s. If it has a uniform acceleration of 10 cm/s², find the distance it travels in 3 seconds.

_______________

${ \huge{ \bold{ \underline{ \underline{ \red{Answer:-}}}}}}$

✒Given : -

• Initial Velocity(u) = 300 cm/s
• Time Taken(t) = 3s
• Acceleration(a) = 10cm/s²

✒To Find : -

• Distance(s) = ?

✒Formula Used : -

$\leadsto\sf{{ \small{ \bold{ \bold{ \bold{ \green{s=ut+\dfrac{1}{2}\:{at}^{2}}}}}}}}$

✒On Substituting Values : -

$\dashrightarrow\sf{s=300\times{3}+\dfrac{1}{{\cancel{2}}}\times{{\cancel{10}}}\times{{(3)}^{2}}}$

$\dashrightarrow\sf{s=900+5\times{9}}$

$\dashrightarrow\sf{s=900+45}$

$\leadsto\sf{{ \large{ \boxed{ \bold{ \bold{ \purple{s=945cm}}}}}}}$

✒Therefore , Distance travelled by the body is 945cm ...