Question

A body has an initial velocity of 3 m/s and has an acceleration of 2 m /s2. Find
the distance travelled by it in 5 s and the velocity then.

Answer 1

Answer:

u = 3m/s

a = 2 m/s^2

t = 5s

v = u+ at

v = 3 + 2*5

v = 3 +10

v = 13 m/s

2as = v^2 - u^2

2*2*s = 13^2 - 3^2

4s = 169 - 9

4s = 160

s = 160/40

s = 40 m

Distance travelled by it = 40 m

Final velocity = 13 m/s

Mark me as brainliest pls

Answer 2

Answer:

In x direction, V

x

=3m/s

In y direction, V

y

=at=1(4)=4m/s.

V

net

=

V

x

2

+V

y

2

=

3

2

+4

2

=5m/s

at an angle tan

−1

(4/3) with initial direction of velocity.