Question

A body has an initial velocity of 3m/ses and has an accleration of 1 m/sec2 normal to the direction of the initial velocity. Then its velocity 4 seconds after the start is

Answer 1

$\large\underline{\underline{\sf Given:}}$

• Initial Velocity (u) = 3m/s

• Accleration (a) = 1m/s²

• Time (t) = 4s

$\large\underline{\underline{\sf To\:Find:}}$

• velocity 4 seconds after the start is = ?

$\large\underline{\underline{\sf Solution:}}$

Initial Velocity is 3m/s this Velocity component will not change by normal accleration.

Hence ,

its component after 4s will be same

i.e 3m/s

This system has normal accleration

1m/s² hence ,

Normal velocity after 4s is = 4 × 1

= 4m/s

Resultant Velocity |V| is :-

$\large\implies{\sf |V|=\sqrt{3^2+4^2} }$

$\large\implies{\sf |V|=\sqrt{25} }$

$\large\implies{\sf |V|=5m/s }$

$\large\underline{\underline{\sf Answer:}}$

•°• Velocity after 4 sec start is 5m/s