a body if mass 600g slides on a rough horizontal surface .If the frictional force is 3N ,then the magnitude of reaction is (take g=10m/s^2)
Answers
Answered by
3
Explanation:
at first........
convert 600g to 0.6kg
therefore use the formula N=mg
therefore
N=0.6 × 10
N=6
therefore 6N
now use the formula
R=√N^2 + √F^2
=√6^2 + √ 3^2
= √36+ 9
= √45
= 6.70....... is the magnitude of reaction
Answered by
2
Answer:
R= 2√10
Explanation:
m=0.6 kg
f= 2N
N= mg
N= 6N
R²=N²+F²
R²=6²+ 2²
R²=36+4
R²=40
R= √4×√10
R= 2√10N
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