A body initially at 80°c cools to 64°c in5 minutes and to 52 °c in 10 minutes the temperature of the bady after 15 mintus will be
Answers
Answered by
2
answer is 42 i think that
Answered by
4
According to Newton law of cooling....
16/5=K[80+64/2 -T].........1
12/5=K[64+52/2 -T].........2
3.2/2.4=K[72-T] ÷K[58-T]..........from 1÷2
We got T=16.....i.e room temperature or atmosphere temperature..
According to given,,,
52-x/5=K[52+x/2 -T]..........3....... where x is the temperature of body after 15 minutes.
Divide eq...2) by 3)......by putting the value of T=16
We got absolutely 43... approximately equal to 42.7
Similar questions