A body initially at rest explodes suddenly into three equal parts.The momenta of two part
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ACCORDING TO LAW OF CONSERVATION OF LINEAR MOMENTUM
M1V1=mv+mv+3mv
v=30ms-1
30kg*0=30m+30m+3xm
assuming masses m,m and 3m and x=velocity of hevier fragment
o=60m+3xm
-60m/3m=x
-20=x
THEREFORE THE HEVIER FRAGMENT FLIES OFF WITH A SPEED OF 20ms-1 in the perpendicular direction.
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Answer:
Explanation:
option d
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