Question

A body initially at rest is accelerated at the rate of 0.2m/s2 for 5seconds under a constant force of 50N. The work done on the body is

Answer 1

Answer:

F= ma

50=m×1/2

m= 100 kg

work done = dp/dt

= m(v-u)/t

u=0m/sec.

v = u+at

v= 1/2 ×5

v = 2.5 m/sec

work done = 100(2.5-0)/5

= 50N