Physics, asked by royekta2002, 1 year ago

A body initially at rest is moving with uniform acceleration a. Its velocity after n seconds is v. The displacement of the body in last 2 seconds is

Answers

Answered by Archana09
7

the distance travelled by the particle in the last two seconds will be = distance travelled by particle in 'n'th second

distance travelled by particle in (n-2)th second

so,

s = (1/2)an2 - (1/2)a.(n-2)2= (1/2)a.[n2 - n2 +4n - 4] = (a/2).[4n - 4]so,s = (2n-2).a = 2a.(n-1) ............................(1)now,velocity, v = acceleration x timev = a x n ora = v/n ..........................(2)so, the displacement in the last two seconds will bes = 2(v/n).(n-1)


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