Question

A body initially at rest, moves with an acceleration of 5 m/s2 for 5 sec. Find the distance travelled in:- 4 seconds 5 seconds 5th second

Answer 1

Answer:

distance traveled in 5th second = Distance traveled in 5 s− Distance traveled in 4 s

Using s=ut+(1/2)at  ^2

 

Distance traveled in 5 s =(1/2)×5×5  ^2

 

                                         =62.5 m

Distance traveled in 4 s =(1/2)×5×4  ^2

 

                                         =40 m

Distance traveled in 5th s =(1/2)×5×5  ^2

 

                                            =62.5 m=S2  −S1

​  

=(62.5−40)m=22.5m

Explanation:

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