A body initially at rest starts moving with a constant acceleration 2m/s calculate the velocity acquired and the distance travelled in 5s
Answers
Answered by
7
Answer:
v=10
Explanation:
v=?
t=5sec
a=2m/s
v-u/t=a
since body is at rest u=0
v/5=2
v=10m
v²=u²+2as
(10)²=2*2*s
100=4*s
100/4=s
25m =s
Answered by
25
Answer :-
As given:-
▪️Initial Velocity = 0
▪️Acceleration = 2 m/s
▪️Time = 5 sec
Now as we know that
• v = u + at
→ v = 0 + 2(5)
→ v = 10
So velocity = 10 m/s
Now as we also know that
→ v² = u² + 2as
→ (10)² = (0)² + 2(2)(s)
→ 100 - 0 = 4s
→ 100 = 4s
→ s = 100/4
→ s = 25
So distance traveled is 25 m
shreyabhatnagar64:
bur we just have to find velocity
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