Question

A body initially at rest starts moving with a constant acceleration 2ms^2 calculate velocity acquired and the distance travelled in 5s

Answer 1

Answer:

velocity = 10m/s distance=25m

Explanation:

given:

u=0(initially at rest), a=2m/s^2, t=5sec. v=u+at: v=0+2*5=10m. s=ut+1/2at^2: s=0*5+1/2*2*(5)^2 s=0+25=25m if it helps you pls mark it as brainiest.