Question

A body, initially at rest, starts moving with a constant acceleration 2 m/s^2. Calculate the velocity acquired and the distance travelled in 5 s.

Answer 1

Answer:-

V = 10m/s

S = 25 m

Given:-

u = 0

a = 2m/s²

T = 5s

To find :-

Velocity acquired and distance travelled.

Solution :-

Since, acceleration is constant so we can use the equation of motion.

$\boxed{\sf{v = u + at}}$

put the given value,

$v = at$

$v = 2 \times 5$

$v = 10m/s$

Now, distance travelled :-

$\boxed{\sf{S = ut + \dfrac {1}{2}at^2}}$

$S = \dfrac {1}{2}at^2$

$S = \dfrac {1}{2}\times 2 .(5)^2$

$S = \dfrac {1}{2}\times 50$

$S = 25 m$

hence, V = 10 m/s

hence, V = 10 m/sS = 25 m.