Question

A body, initially at rest, starts moving with a constant acceleration 2 m/s2. Calculate

(i) the velocity acquired and (ii) the distance travelled.
Please give the correct answer.​

Answer 1

Answer:

Initial velocity, u=0

Initial velocity, u=0Acceleration, a=2ms

Initial velocity, u=0Acceleration, a=2ms −2

Initial velocity, u=0Acceleration, a=2ms −2

Initial velocity, u=0Acceleration, a=2ms −2 Time, t=5s

Initial velocity, u=0Acceleration, a=2ms −2 Time, t=5sDistance traveled, s=ut+

Initial velocity, u=0Acceleration, a=2ms −2 Time, t=5sDistance traveled, s=ut+ 2

Initial velocity, u=0Acceleration, a=2ms −2 Time, t=5sDistance traveled, s=ut+ 21

Initial velocity, u=0Acceleration, a=2ms −2 Time, t=5sDistance traveled, s=ut+ 21

Initial velocity, u=0Acceleration, a=2ms −2 Time, t=5sDistance traveled, s=ut+ 21 at

Initial velocity, u=0Acceleration, a=2ms −2 Time, t=5sDistance traveled, s=ut+ 21 at 2

Initial velocity, u=0Acceleration, a=2ms −2 Time, t=5sDistance traveled, s=ut+ 21 at 2

Initial velocity, u=0Acceleration, a=2ms −2 Time, t=5sDistance traveled, s=ut+ 21 at 2 s=(0×5)+(

Initial velocity, u=0Acceleration, a=2ms −2 Time, t=5sDistance traveled, s=ut+ 21 at 2 s=(0×5)+( 2

Initial velocity, u=0Acceleration, a=2ms −2 Time, t=5sDistance traveled, s=ut+ 21 at 2 s=(0×5)+( 21

Initial velocity, u=0Acceleration, a=2ms −2 Time, t=5sDistance traveled, s=ut+ 21 at 2 s=(0×5)+( 21

Initial velocity, u=0Acceleration, a=2ms −2 Time, t=5sDistance traveled, s=ut+ 21 at 2 s=(0×5)+( 21 ×2×5

Initial velocity, u=0Acceleration, a=2ms −2 Time, t=5sDistance traveled, s=ut+ 21 at 2 s=(0×5)+( 21 ×2×5 2

Initial velocity, u=0Acceleration, a=2ms −2 Time, t=5sDistance traveled, s=ut+ 21 at 2 s=(0×5)+( 21 ×2×5 2 )=25m

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Answer 2

Answer:

$\huge \sf \underline{note \ \: : }$

$\sf \: v = u + a \times t</p><p></p><p>$

$\sf \: Initial Velocity \ \: : u\: (m /s)</p><p></p><p>$

$</p><p></p><p> \sf \: Final Velocity \ \: : v \: (m /s)</p><p></p><p></p><p>$

$\sf \: Acceleration \ \: : a$

$\sf \: Time \ \: : t \: (s)</p><p></p><p></p><p></p><p></p><p></p><p></p><p>$

$\huge \sf \underline{given\ \: : }$

$\sf \: initial \: velocity \: (u)\ \: : 0$

$\sf \: acceleration \: (a) \ \: : 2 {ms}^{ - 2}$

$\sf \: time \: (t) \ \: : 5 \: sec$

$\huge \sf \underline{let \: us \: solve \ \: : }$

$\sf \: distance \: travelled \: (s) \ \: :$

$\sf \: ut + \frac{1}{2} {a(t)}^{2}$

$\sf \to s = (0 \times 5) + \frac{1}{2} \times (2 \times {5}^{2} )$

$\sf \to0 + { \not \frac{1} {{2} }} \times \not{2} \times 25$

$\sf \to0 + 1 \times 25$

$\red {\sf{{s = 25 \: m}}}$