Question

A body, initially at rest, starts moving with a constant
acceleration 2 m s-2. Calculate : (i) the velocity
acquired and (ii) the distance travelled in 5 s.
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Answer 1

okay ,so

by , v = U + at

• v = 0 + 2 × 5.
• [ u = 0 as body started from rest]
• v = 10 m/s

2) S = ut + 1/2 at²

S = 0 + 1/2 × 2(5)² [ u= 0]

S = 25 m.

hope it helps

Answer 2

HERE IS YOUR ANSWER

(1)GIVEN:-

a= 2ms-2

u=0 ms-1

v=?

s=?

V=U+AT

V=0+2×5

V=10ms-1

(2)DISTANCE OR (S)

S=U×T+1/2AT2

S=0×5+1/2×2×5×5

S=25 m

THE DISTANCE TRAVELLED PER 5 S IS 25 M

HOPE IT HELPS !!

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