Question

a body initially at rest starts moving with acceleration of 2ms find velocity acquired and the distance travelled in 5 sec​

Answer 1

Step-by-step explanation:

a/q

u=0

a=2ms²

t=5 sec

s=ut+1/2at²

s=0*5+1/2*2*5*5

s=1/2*2*25

s=25 metres is the distance traveled

a=v-u/t

2=v-0/5

v=10m/s is the velocity acquired

Answer 2

Initial Velocity (u) = 0 m/s

Final velocity (v) = ??

Acceleration (a) = 2m/s²

Time(t) = 5 s

We know that:

a = (v-u)/t

2 = (v-0)/5

On solving:

10m/s = v

Final velocity = 10m/s

Distance (s) = ???

s = u×t+½×a×t²

s = 0+½×2×(5)²

s = ½×2×25

s = 25m

Here is your answer and hope it surely helps you.