Question

A body initially at rest take 10 seconds to increase its

velocity to 50 m/s. Find the average acceleration produced

in the body​

Answer 1

Given :

Initial velocity of the body = zero

time taken = 10s

final velocity of the body = 50m/s

To find :

The average accerlation produced by the body

Solution :

Acceleration is measured as the rate of change of velocity.

• It is a vector quantity having both magnitude and direction
• SI unit of accerlation is metre per second

The average accerlation is defined as the ratio of change of velocity over a time interval to the time taken.

$\boxed{ \sf{Average \: accerlation = \dfrac{Change \: in \: velocity}{time}}}$

that is,

$\leadsto{ \sf{a = \dfrac{v - u}{t}}}$

$\leadsto{ \sf{a = \dfrac{50 - 0}{10}}}$

$\leadsto{ \sf{a = \dfrac{50}{10}}}$

$\leadsto{ \sf{a = 5 m {s}^{ - 2} }}$

thus, the average accerlation produced by the body is 5m/s²

Answer 2

Given:

Initial velocity of the body = zero

time taken = 10s

final velocity of the body = 50m/s

To find:

Average accerlation produced by the body=?

Solution:

The average accerlation is defined as the ratio of change of velocity over a time interval to the time taken.

$\boxed{ \sf{Average \: accerlation = \dfrac{Change \: in \: velocity}{time}}}$

that is,

$\leadsto{ \sf{a = \dfrac{v - u}{t}}}$

$\leadsto{ \sf{a = \dfrac{50 - 0}{10}}}$

$\leadsto{ \sf{a = \dfrac{50}{10}}}$

$\leadsto{ \sf{a = 5 m {s}^{ - 2} }}$

Thus, your answer is 5ms‐²

Hope so it will help.....