A body initially at rest travell a distence 100 m in 5sec with constant acceleration and final velocity at the end of 5 sec
Answers
Answered by
0
★ Hey mate ★
here is your answer !!!
u = 0
v = 100 m
time = 5sec
a = v - u / t
100 -0 / 5 sec
= > 100 / 5 sec
20 m / s
now ,
u = 0
so ,
s = 1 / 2 × a × t²
=> 1 / 2 × 20 m / s² × 5 × 5 s
=> 10 × 5 × 5 sec
=> 50 × 5 m
=> 250 m
hope it helps you dear !!!
thanks !!!
here is your answer !!!
u = 0
v = 100 m
time = 5sec
a = v - u / t
100 -0 / 5 sec
= > 100 / 5 sec
20 m / s
now ,
u = 0
so ,
s = 1 / 2 × a × t²
=> 1 / 2 × 20 m / s² × 5 × 5 s
=> 10 × 5 × 5 sec
=> 50 × 5 m
=> 250 m
hope it helps you dear !!!
thanks !!!
Answered by
0
V = at
V = 20*5 = 100m/s
V = 20*5 = 100m/s
Similar questions
World Languages,
7 months ago
Math,
7 months ago
Physics,
7 months ago
Math,
1 year ago
Political Science,
1 year ago