Question

a body initially at rest travels a distance 100 m in 5 s with a constant acceleration.calculate

1) the acceleration and
2) the final velocity at the end of 5s

Answer 1

given:
u=0
s=100
t=5
s=ut+1/2at²
100=0+1/2a*25
200=25a
a=8
the final velocity =u+at
=8*5
=40

Answer 2

Given,
U=0
S=100m
t=5s
So,s=ut+1/2at^2
100=0×5+1/2×a×5×5
a=8m/s^2
Again,v=u+at
V=0+8×5
V=40m