Question

A body initially at rest travels a distance 100m in 5sec with a constant acceleration. Calculate the acceleration and final velocity at the end of 5sec.

Answer 1

Explanation:

s=ut+(1/2)at ^2

100=(1/2)×a×5 ^2

a=8 m/s

2

v=u+at

v=0+8×5=40ms ^−1

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