Question

A body initially at rest travels a distance of 100m in 5 seconds with a constant acceleration. calculate acceleration and final velocity at the end of 5 seconds​

Answer 1

Answer:

=ut+(1/2)at

2 100=(1/2)×a×5

2a=8 m/s

2v=u+at

v=0+8×5=40ms−1

Sorry fot my sh*tty typing skills ;)