Question

A body initially at rest travels a dustance 100m in 5s with a constant acceleration. Calculate: (i) acceleration (ii) final velocity at end of 5s

Answer 1

Heya Mate

here is your answer

Refers to Attachment

Answer 2

Given, Initial velocity u = 0

Distance S = 100m

Time taken t = 5s

(i) Acceleration

$\rm{from \: equation \: of \: motion \: \: s = ut + \frac{1}{2} a {t}^{2} }$

$\rm{100 = 0 \times 5 + \frac{1}{2} \times a \times {5}^{2} }$

$\rm{100 = \frac{1}{2} \times 25a }$

$\rm{or \: \:acceleration \: a = \frac{100 \times 2}{25} = 8m {s}^{ - 2} }$

$\fbox{ \rm{ \therefore acceleration = 8m {s}^{ - 2} }}$

(ii) Final velocity

From equation of motion v = u + at

$\rm{Final \: velocity = 0 + 8 \times 5}$

$\fbox{\rm{ \therefore \: Final \: velocity = 40m {s}^{ - 1} }}$