Question

A body initially ay rest travels a distance of 100m in 5s with a constant acceleration.calculate the acceleration and the velocity at the end of 5s

Answer 1

From equation of motion 2nd
S = ut + 1/2 at²

100 = 0*5 + a *25/2
100 = 25a/2

a = 2*100/25
a = 8 m/s²

where u stands for initial speed which is 0 m/s cause car is at rest
t stands to total time taken and a is the acceleration

hence required acceleration of the car is 8m/s²

now for velocity(v) we can use 3rd equation of motion
v² = u² + 2as
v² = 2*8*100
v² = 1600

hence v = 40m/s

Answer 2

howdy!!

your answer is ----

acceleration a = 8m/s^2


and , velocity at 5s is 40m/s

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hope it help you